# CONFIRM 2012 WACE MATHS QUESTIONS AND ANSWERS

Filed in Uncategorized by on April 26, 2012

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(4a)total dices = 40, (R)=?, (R)=?, pr(R) + pr(W) = 1, pr(W) = 1- (1/4) = 3/4, n(w) = 3*40, n(w) = (3*40)/4 = 30.

for the problem of red to be 1/3, n(R) + n (Rraistopower 1)/ 40 = 1/3, No of white=30.

N:B: FOR NO. 10 Please note that bar means Minus (-) on top of the number or Variable and comma means next line which means each of them are unda.

E.g 60-64 is unda Class interval, then 65-69 is unda 60-64, etc . So comma means unda. No 10 is a table.

(7aii) place of intersection = 1.2 (7b) x raistopower 2+bx+18 , (x+2)(x+c), (x+6)(x+3), x raistopower 2+3x+6x+18, x raistopower 2+9x+18, c=3, b=9

(11a) length from A & B= (3n-1)m length B &C = (2n+1)m perimeter (p) = 2 (L+b) p=2 ((3n-1) + (2n+1) ) =2 (5n)=10n, p=10n—-> equation (1),

A = B = (3n-1)(2n-1) —->equation(2), P+ B = 135, 10n + 3n – 1 + 6n + 3 = 135, 19n = 135 – 2, n = 7

(11b.) r = 14cmfor cylinder, l = 22cm for cube: total surface area of cylinder = 2πr (2 pie r) (r + h) and volume of cube = l^3, 2πrh = l^3,= 2*22/7*14*h = 22*22*22, 88h=10648, h=10648/88=121cm..

ratio of area of cylinder to cone = 2πr(r+h) : 6l^3, 2(22/7)* 14(14 +21) :6(22) ^2, 88*28 :2904, = 308:363 NOTE THAT THIS SYMBOL (π) IS PIE

(7aiii.) y-(3x)/4 = 3, y – 3(2)/4 = 3, 4y – 6 =12, y = 4.5 (iv.) y – (3x)/4 = 3, y – 3(3)/4 = 3, 4y = 21, y = 5.25

@ means the proced. of the solution below

(13a) From angle SQR, applying pythogoras theorem QR square 2 = QS square 2 + SR square 2, 13 square 2 = QS square 2 + 5 square 2, 169 = QS square 2 + 25, QS square 2 =169 – 25 =144,

But angle (a) in SQR =?, Sin a = opp/hyp, sin a = 5/3, a = sin (square-1) (5/13) = 22.62º, and θ + a = 180º, θ= 180 – a =180 – 22.62, θ = 157.38º,

Cosine rule: @PS @2= @PQ @2 + QS @2 – 2 @PQ @, cos θ, @ps @2 = 6sq2 + 12sq2 – 2(6-*12) cos θ, @ps @2 = 36 + 144 – 144 cos θ, @ps @2 = 180 – 144 cos 157.38, @ps @ = 180 – (-132.923) @ps @sq2 = 180 + 132.923, @ps @sq2 = 312.923, @ps @ = 17.7 to 1dp.

(4b.) Let the cost of price be N50 let the selling price(sp) be N600.

The profit is 20% sp – gain + cp=sp. where (sp = selling price and cp = cost price) for those who don’t understand. 20/100*600 Therefore profit = 120 =6 sp – gain = cost price therefore 600 – 120 = cp cp = 480 therefore = 9.6 (Approximately)