# CONFIRM 2012 NECO MATHEMATIC QUESTIONS AND ANSWER

Filed in Uncategorized by on June 17, 2012

(4a)x=1380-130=50(corresponding angle), y=180-125,=55 degree(corresponding angle) (4b) 1/3(x+8)-1/7(2x-4)less or equal to 1, multiply both sides by 21(Lcm). 7x+56-6x+12 less or equal to 21, x less or equal to 21-56-12., x=-47.

12.)Abu=2/7 Abu=1/6 Ola=3/5 (abu)Λ1=5/7 (ola)Λ1=2/5 (a).pr(all score below 70%) =5/7*5/16*2/5 =5/56.

(b).pr(at most score70%) =(5/2*1/6*3/5)+(5/6*2/7*3/5) +(2/5*2/7*1/6 5/70+10/70+20/70 5/70+10/70+20/70 15/70+2/70=17/70.

(c).pr (all score 70%) =2/7*1/6*3/5 =2/70=1/35

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11-20 DBABBAEECA

31-40 DAEBDBDAEC

Please note that the objective hav not confirm yet.

(7a) R=kl, r=0.6, k=0.8, R=0.08L. R=0.08*35.5=2.85 ohms

(7bi) Tn= arΛn-1, a=10/3, r=1/2. T8= 10/3*1/128=10/384.

(7biii) sn=(a(1-rΛn))/1-r= (10/3(1-(1/2)Λ10))/1-1/2=( (10/3)(1-1/1024))= 1705/256

(N11a) Log27base3=log64base1/4+nlog3 1/81 Log3 2base3=log4 3base1/4+-4nlog3base3 2=3log4base1/4-4n 4n=3log16base14-2 4n=12-2 4n=10 N=10/4 =2 whole number 1/ 2

(9B) Dist AB=titapieR/180degree 864000=(x-25)20108.8(x-25)=86400,20108.8 X-25=43 X=43+25 X-68degree,d latutude of A is 68degree

(N09ai ) dst bc=tita pieRcosa/180 =80times3.142times640cos2/180 =1452980.9/180=8099.9=8100km.

(N09ii) Chord bc =2crostita /2 =2*64cos25sin40degree.

(1b) ATB=36 degree(base angle of isosceles triangle) BAT=180 degree= 180 degree-(36+36) (sum of angle in a triangle)= 180-72 BAT=180-72=108 degree BTC= 72 degree (base angle of isosceles triangle) TBC=x(angle in alternate segment)= 180-(72+72)= 180-144=36 degree

(11b)

Abu=2/7

Abu=1/6

Ola=3/5 (abu)Λ1=5/7 (ola)Λ1=2/5

(a).pr(all score below 70%) =5/7*5/16*2/5 =5/56.

(b).pr(at most score70%) =(5/2*1/6*3/5)+(5/6*2/7*3/5) +(2/5*2/7*1/6 5/70+10/70+20/70 5/70+10/70+20/70 15/70+2/70=17/70.

(c).pr (all score 70%) =2/7*1/6*3/5 =2/70=1/35

(6ai)#1000.90 *12=#12010.80=#12010.80

(6ii) p:e= 16:5, petrol exp= (16/21)*1700= #1295.24, electricity expenses= 1700-1295=# 404.76 Difference= 1295.24-404.76= #890.48

(6b) Tn=n+(n-1)d, T5= 8+(5-1)d=32, 8+4d=32 4d=24, d=6. X=8+6=14. Y=14+6=20 Z=20+6=20